0=2(x^2+4x-480)

Solution for 0=2(x^2+4x-480) equation:

0=2(x^2+4x-480)

We move all terms to the left:

0-(2(x^2+4x-480))=0

We add all the numbers together, and all the variables

-(2(x^2+4x-480))=0


We calculate terms in parentheses: -(2(x^2+4x-480)), so:

2(x^2+4x-480)

We multiply parentheses

2x^2+8x-960

Back to the equation:

-(2x^2+8x-960)


We get rid of parentheses

-2x^2-8x+960=0

a = -2; b = -8; c = +960;
Δ = b2-4ac
Δ = -82-4·(-2)·960
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7744}=88$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-88}{2*-2}=\frac{-80}{-4}
=+20
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+88}{2*-2}=\frac{96}{-4}
=-24
$